Question of the Day

What will be the product formed when phenol reacts with Br₂ in CCl₄ medium?

Because the non-polar solvent (i.e. CCl₄) induces a weaker dipole in Br-Br as compared to the polar solvent (i.e. water), a weaker electrophile (Br+) is produced that undergoes electrophilic aromatic substitution with the benzene ring. Consequently, we get mono-bromination with Br (in CCl₄) with compared with tri-bromination Br (in aq.).

3- Bromophenol 4- Bromophenol 3,5- Dibromophenol 2,4,6- Tribromopheno None of the above